n(HCl) = 896/22.4 = 40mol
所以m(HCl) = 36.5*40 = 1460g
水的质量 = 1*2000 = 2000g
溶液质量 = 1460 + 2000 = 3460g
溶液体积 = 3460/1.15 = 3008.7ml = 3L
所以该盐酸的物质的量浓度 = 40/3 = 13.3mol/L
盐酸中HCl的质量分数 = 1460/3460 = 42.2%