=3-(√2+1)+(√2+1)/(√2+1)(√2-1)
=3-(√2+1)+(√2+1)/(2-1)
=3-(√2+1)+(√2+1)
=3答案得负一不可能的三分之一的负一次方减根号二加1加【根号2减一1 】分之一得多少=3-√2+1+(√2+1)/(√2+1)(√2-1)=3-√2+1+(√2+1)/(2-1)=3-√2+1+(√2+1)=5