∫1/(x^3-4x^2+5)dxx^3-4x^2+5 = (x+1)(x^2-5x+5)let 1/(x^3-4x^2+5)= A/(x+1) + (Bx+C)/(x^2-5x+5)=>1= A((x^2-5x+5) +(Bx+C)(x+1)put x=-1A=1/11coef.of constant1=5A+ CC = 6/11put x=11= A+2B+2C1= 1/11+2B+12/1...