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己知a^3m=,b^3n=2,求(a^2m)^3+(b^n)^3-a^2m·b^n·a^4m·b^2n的值
人气:203 ℃ 时间:2019-08-18 14:12:41
解答
(a^2m)^3+(b^n)^3-a^2m×b^n×a^4m×b^2n
=a^6m+b^3n-a^6m*b^3n
=(a^3m)^2+b^3n-(a^3m)^2*b^3n
=9+2-9*2
=-7
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