求圆心在直线3x+2y=o上,并且与x轴交点分别为(-2,0)(6,0)的圆的方程
人气:465 ℃ 时间:2019-08-21 20:41:08
解答
与x轴交点分别为(-2,0)(6,0)的圆
圆心必在直线 x=(-2+6)/2=2上.
代入到3x+2y=0,得:y=-3.
即圆心坐标是:(2,-3)
半径=根号[(2+2)^2+(-3-0)^2]=5
所以,圆方程是:(x-2)^2+(y+3)^2=25.
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