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化简:sin^2α×tanα+cos^2α×cotα+2sinα×cosα
人气:144 ℃ 时间:2019-12-24 23:43:18
解答
原式=sin^2a*sina/cosa+cos^2a*cosa/sina+2sina*cosa=sina^3a/cosa+cos^3a/sina+2sina*cosa=(通分)(sin^4a+cos^4a+2sin^2a*cos^2a)/sina*cosa=(sin^2a+cos^2a)^2/sina*cosa=1/sina*cosa
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