求微分方程DX分之DY+YX方=0满足Y}X=1=1的特解
人气:134 ℃ 时间:2020-05-19 08:42:41
解答
dy/dx=yx^2
dy/y=x^2dx
lny=x^3/3+lnC
y=Ce^(x^3/3)
y(1)=1代入:C=e^(-1/3)
y=e^(x^3/3-1/3)
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