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lim(x->0)e^[-1/x^2]为多少?
人气:122 ℃ 时间:2020-06-20 12:35:03
解答
lim(x→0) e^(-1/x²)
=lim(x→0) e^-(1/x²)
=e^-(1/0)
=e^-∞
=1/∞
=0

lim(x→0) e^(-1/x²)
=lim(x→0) 1/e^(1/x²)
=1/e^(1/0)
=1/e^∞
=1/∞
=0
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