ln(lim x*e^(1/x^2))=lim(ln x*e^(1/x^2))这时x->0+以下省略limln(x*e^(1/x^2))=lnx+1/x^2=(x^2lnx+1)/x^2应用洛必达法则易求得lim x^2lnx=0这样就可以求得ln(lim x*e^(1/x^2))=lim(ln x*e^(1/x^2))=+∞所以lim x*...