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数学
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已知a b c均为实数且|a-1|+﹙根号b²-2b+1﹚﹢c²+4=4c
人气:361 ℃ 时间:2019-11-09 15:53:03
解答
|a-1|+﹙根号b²-2b+1﹚﹢c²+4-4c=0|a-1|+﹙根号b²-2b+1﹚﹢(c-2)^2=0因:|a-1|≥0,﹙根号b²-2b+1﹚≥0,(c-2)^2≥0所以:|a-1|=0 得:a=1﹙根号b²-2b+1﹚=0 得:b=1(c-2)^2=0 得:c=2...
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