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log4(sin3π/4)+log9[tan(-5π/6)]的值是多少
人气:158 ℃ 时间:2020-09-10 11:50:39
解答
log4(sin3π/4) + log9[tan(-5π/6)]=log4 (√2/2) + log9 [-tan(5π/6)]=log4 (√2/2) + log9 [-(-√3/3)]=log4 (√2/2) + log9 (√3/3)=log(2^2) [2^(-1/2)] + log(3^2) [(3)^(-1/2)]=[(-1/2)/2]log2 2 + [(-1/2)/...
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