求(log3^2 + log9^2)×(log4^3 + log8^3)的值.
请给出过程,谢谢!
人气:462 ℃ 时间:2019-08-28 04:50:27
解答
(log3^2 + log9^2)×(log4^3 + log8^3)
=(log3^2+0.5log3^2)×(0.5log2^3+1/3*log2^3)
=3/2*log3^2×5/6*log2^3
=5/4
推荐
- 化简(log4(3)+log8(3))(log3(2)+log9(2))
- 求值(log3(2)+log9(2))*(log4(3)+log8(3))
- 【(log4)^3+.(log8)^3】【.(log3)^2+.(log9)^2】=几啊
- (log3^2 + log9^4)×(log4^3 + log8^3)
- (log4(3)+log8(3))(log3(2)+log9(2))-log4(3)×log1/3(四次根号32)
- 已知向量a=(1,1),b=(1,0),c满足a·c等于0,且|a|=|c|,b·c>0.
- 含铝90%的铝合金1.5g,跟40mL6mol/L的盐酸充分反应(其它不反应),过滤除去不溶物,
- X,Y独立,EX=EY=0,DX=DY=1,则E(X+2Y)^2=?
猜你喜欢