A(n+1)=S(n+1)-Sn=-(n+1)(n+1-2)-[-n(n-2)]=-2n+1,所以An是等差数列.An=-2n+3,差d=-2S1=a1=1a1,a3,a5,a7,a9可全部算出来之后求和,也可用如下方法:a1,a3,a5,a7,a9是首项为a1,公差为2d的等差数列,此数列共有五项,代入...