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∫ln﹙x²+1﹚dx
人气:468 ℃ 时间:2020-03-06 02:17:49
解答
∫ln﹙x²+1﹚dx
=xln(x²+1)-∫[2x²/﹙x²+1﹚]dx
=xln(x²+1)-2∫[1-1/﹙x²+1﹚]dx
=xln(x²+1)-2x+2arctanx+ c
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