化简25^（1/3log以5为底 27的对数+log以125为底8的对数）_数学解答

化简25^（1/3log以5为底 27的对数+log以125为底8的对数）

人气：481 ℃　时间：2019-08-21 10:30:52

解答

原式=25^[log(125)27+log(125)8]
=25^[log(125)27*8]
=25^[3log(125)3*2]
=25^[3*(1/3)log(5)6]
=25^[log(5)6]
=25^[2log(25)6]
=25^[log(25)36]
=36