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求方程组0.5x+0.8y=4.7 0.6x+0.12y=6.6
人气:349 ℃ 时间:2020-06-21 11:47:32
解答
0.5x+0.8y=4.7.(1)
0.6x+0.12y=6.6.(2)
(1)*6:
3x+4.8y=28.2.(3)
(3)*5:
3x+0.6y=33.(4)
(3)-(4):
4.2y=-4.8
y=-8/7
代入(1):
x=393/35
综上所述,
{x=393/35
{y=-8/7
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