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已知x+y=6,xy=-2,求(x的4次方-y的4次方)除以x²+y²/xy除以(6x-6y)的值
人气:286 ℃ 时间:2020-03-15 22:44:28
解答
原式=(x²+y²)(x²-y²)*xy/(x²+y²)÷(6x-6y)
=xy(x+y)(x-y)÷6(x-y)
=xy(x+y)/6
=-2×6/6
=-2
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