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因式分解要用【分组分解法】解题、要有过程
1.a(a-1)(a-2)-6
2.已知x²+10xy+25y²-1=0化简x³+5x²y+x²
人气:282 ℃ 时间:2020-02-04 00:46:44
解答
1.(a²-a)(a-2)-6
=a³-2a²-a²+2a-6
=(a³-3a²)+(2a-6)
=a²(a-3)+2(a-3)
=(a²+2)(a-3)
2.x²+10xy+25y²-1=0
(x+5y)²-1=0
(x+5y+1)(x+5y-1)=0
得x+5y+1=0,或x+5y=1
由x³+5x²y+x²变得x²(x+5y+1)
∴x³+5x²y+x²=x²(x+5y+1)=0或2x²
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