> 数学 >
分解因式:3x^2+5x-8 x^2(x^2+2y^2)-3y^4 -6x^2-12-x 6x^2-7x+2
分解因式:3x^2+5x-8 x^2(x^2+2y^2)-3y^4 -6x^2+12-x 6x^2-7x+2
人气:377 ℃ 时间:2020-06-28 18:05:49
解答
⑴3x²+5x-8
=3x²-3x+8x-8
=3x﹙x-1﹚+8﹙x-1﹚
=﹙x-1﹚﹙3x+8﹚.
⑵x²﹙x²+2y²﹚-3y^4
=x^4+2x²y²-3y^4
=﹙x²﹚²-x²y²+3x²y²-3﹙y²﹚²
=x²﹙x²-y²﹚+3y²﹙x²-y²﹚
=﹙x²-y²﹚﹙x²+3y²﹚
=﹙x+y﹚﹙x-y﹚﹙x²+3y²﹚.
⑶-6x²+12-x
=-﹙6x²+x-12﹚
=-﹙2x+3﹚﹙3x-4﹚
⑷6x²-7x+2
=6x²-3x-4x+2
=3x﹙2x-1﹚-2﹙2x-1﹚
=﹙2x-1﹚﹙3x-2﹚.
推荐
猜你喜欢
© 2025 79432.Com All Rights Reserved.
电脑版|手机版