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计算:1/[a(a+1)]+1/[(a+1)(a+2)]+1/[(a+2)(a+3)+...+1/[(a+2006)(a+2007)]
人气:161 ℃ 时间:2020-10-01 15:32:42
解答
1/[a(a+1)]=1/a-1/(a+1)1/[(a+1)(a+2)]=1/(a+1)-1/(a+2)1/[(a+2)(a+3)]=1/(a+2)-1/(a+3)……1/[(a+2005)(a+2006)]=1/(a+2005)-1/(a+2006)1/[(a+2006)(a+2007)]=1/(a+2006)-1/(a+2007)原式1/[a(a+1)]+1/[(a+1)(a+2)]+...
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