> 数学 >
已知a=m/2+1,b= m/2+2,c= m/2+3,求a^2+2ab+b^2-2ac-abc+c^2的值
人气:461 ℃ 时间:2020-03-26 09:03:11
解答
a^2+2ab+b^2-2ac-abc+c^2 =(a+b)^2-2c(a+b)+c^2+2bc-abc =(a+b-c)^2+bc(2-a) =(m/2+1+m/2+2-m/2-3)^2+(m/2+2)(m/2+3)(2-m/2-1) =m^2/4+(m^2/4+5m/2+6)(1-m/2) =(m^2)/4+(m^2)/4+5m/2+6-(m^3)/8-)(5m^2)/4-3...
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版