f(x)=cos(√3x+∮),则f’(x) =-√3sin(√3x+∮),f(x)+f’(x) =cos(√3x+∮) -√3sin(√3x+∮)=2[1/2 cos(√3x+∮)- √3/2sin(√3x+∮)]=2 cos(√3x+∮+π/3)f(x)+f’(x)是奇函数,则需∮+π/3=kπ+π/2,k∈Z.∮=kπ+...