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若点P(cosa,sina)在直线x+2y=0上,则cos2a+sin2a=?
A.-1/5 B.-1/2 C.1/5 D.1/2
人气:436 ℃ 时间:2020-08-30 15:11:18
解答
点P(cosa,sina)在直线x+2y=0上,即有cosa+2sina=0
tana=-1/2
则cos2a+sin2a=(cos^2a-sin^2a+2sinacosa)/(cos^2a+sin^2a)
=(1-tan^2a+2tana)/(1+tan^2a)
=(1-1/4-1)/(1+1/4)
=-1/5
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