个a十b百c1如果这个三位数能被11整除 那么a+c=b(100c+10b+a)=(a^2+b^2+c^2)*11100c+10c+11a=11a^2+11a^2+11c^2+22ac+11c^2110c+11a=22a^2+22c^2+22ac10c+a=2a^2+2c^2+2acb0c=1,11>100+10b+a-11a^2-11b^2-11>0 a=1 11...