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分解因式(x2+2x)(x2+2x-2)-3
人气:165 ℃ 时间:2020-09-30 12:14:00
解答
设x2+2x=t
(x2+2x)(x2+2x-2)-3
=t(t-2)-3
=t^2-2t-3
=(t-3)(t+1)
=(x^2+2x-3)(x^2+2x+1)
=(x+3)(x-1)(x+1)^2
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