1,2,-3,-4,5,6,-7,-8,9,10…-2003,-2004,2005,2006…是从一开始的连续整数中依次两个取正.两个去负数写下去的一串数,则前2009个数的和是多少?
人气：126 ℃ 时间：2019-11-13 22:48:21
解答
1+2-3-4=-4 5+6-7-8=-4 .
4个一组 2008/4=502
502*（-4）=-2008
-2008+2009=1
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