解方程(2x-1)^2-10(2x-1)+25=0 （1+√2）x^2-(1-√2)x=0 用分解因式做啊_数学解答

解方程(2x-1)^2-10(2x-1)+25=0 （1+√2）x^2-(1-√2)x=0 用分解因式做啊

人气：230 ℃　时间：2020-09-19 07:33:11

解答

(2x-1)^2-10(2x-1)+25=0 (2x-1-5)²=0(2x-6)²=0∴x=3（1+√2）x^2-(1-√2)x=0 x[(1+√2)x-(1-√2)]=0x=0 (1+√2)x-(1-√2)=0x=0 x=(1-√2)/(1+√2)=(1-√2)²/(1-2)=-(1-√2)²=-1+2√2-2=2√2-3∴...