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数学
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求函数y=2sin(3x+pai/4)的图像的单调区间,对称轴,对称中心
人气:478 ℃ 时间:2019-09-27 06:50:51
解答
由于T=2π/ω=2π/3为函数周期令-π/2≤3x+π/4≤π/2,得 -π/4≤x≤π/12即当2kπ/3-π/4≤x≤2kπ/3+π/12时,函数为增函数令π/2≤3x+π/4≤3π/2,得π/12≤x≤5π/12即当2kπ/3+π/12≤x≤2kπ/3+5π/12时,函数...
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