已知x^3+xy^2+x+x^2y+y^3+y=0,求5x-6y/3x+4y的值._数学解答

已知x^3+xy^2+x+x^2y+y^3+y=0,求5x-6y/3x+4y的值.

人气：308 ℃　时间：2019-10-05 12:29:38

解答

(x³+y³)+(x²y+xy²)+(x+y)=0(x+y)(x²-xy+y²)+xy(x+y)+(x+y)=0(x+y)(x²-xy+y²+xy+1)=0(x+y)(x²+y²+1)=0x²+y²+1≥1>0即不会等于0所以x+y=0y=-x原式=(5x+6...