∫ x(lnx)² dx=∫ (lnx)² d(x²/2)令u=(lnx)² ,v=x²/2,则du = 2lnx * (1/x) dx 由分部积分公式∫u dv = uv - ∫v du∫ x(lnx)² dx=∫ (lnx)² d(x²/2)=(x²/2)(lnx)²...