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计算:(a^2-8a+16)/(9-a^2 ) ÷(16-a^2)/(9+6a+a^2 )
人气:169 ℃ 时间:2020-03-26 06:26:02
解答
原式=(a-4)²/(a+3)(a-3)÷[-(a+4)(a-4)/(a+3)²]=-(a-4)²/(a+3)(a-3)×(a+3)²/(a+4)(a-4)=-(a-4)/(a-3)×(a+3)/(a+4)=(-a²+a+12)/(a²+4a-12)
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