c(H+)=1.33*10^-3 mol/L,pH=2.88
Ka=c(H+)*c(CH3COO-)/c(CH3COOH)
c(CH3COOH)=0.1mol/L
c(H+)=√【Ka*c(CH3COOH)】=√(1.76*10^-5*0.1)=1.33*10^-3 mol/L
pH=-lgc(H+)=2.88