>
数学
>
化简sin^4x-sin^2x+cos^2x
人气:268 ℃ 时间:2020-03-20 18:11:40
解答
sin^4x-sin^2x+cos^2x
=sin^2x(sin^2x-1)+cos^2x
=-sin^2xcos^2x+cos^2x
=cos^2x(1-sin^2x)
=cos^4x
推荐
化简sin^4x+sin^2xcos^2x+cos^2x=?(请写过程)
化简:cos^4x+sin^2xcos^2x+cos^2x
化简(sin^2x-cos^4x+cos^2x-sin^4x)/(sin^2x-cos^6x+cos^2x-sin^6x)
化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x
化简cos^4x+sin^2xcos^2x+sin^2x
()欢呼欢乐()()飞扬()纷飞 欢庆()()欢快()飞舞 放飞()
描写人的外表
鲍叔荐管仲与这个典故相关的成语是
猜你喜欢
诸葛亮做丞相,鞠躬尽瘁死而后已的下联
get sth from sb
keep healthy=keep fit=keep in good healthy 还等于什么?全部写出来!
劝告你不听一一( ) 写“一”字开头的成语.
求一椭圆轨迹方程
艺术幼儿园用英语怎么说
九分之八的倒数与二十七分之十六的和是多少?
见异思迁的迁是什么意思
© 2025 79432.Com All Rights Reserved.
电脑版
|
手机版