第n项是n×(n+1)=n²+n所以原式=(1²+1)+(2²+2)+……+(2002²+2003)=(1²+2²+3²+……+2002²)+(1+2+……+2003)=2002×(2002+1)×(2×2002+1)/6 + 2003×(2003+1)/2=2678686011...