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已知dy/dx=2/2-cosy,求二阶导数d^2y/dx^2
人气:402 ℃ 时间:2019-08-19 19:54:02
解答
dy/dx=2/(2-cosy)
即:
y'=2/(2-cosy)
y''
=-(2-cosy)'/(2-cosy)^2
=(cosy)'/(2-cosy)^2
=-siny*y'/(2-cosy)^2,将y'代入得到:
d^2y/dx^2 =y''=-2siny/(2-cosy)^3.
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