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计算:(a+2)(a-2)(a^4+4a^2+16) 和 (x^2+2xy+y^2)(x^2-xy+y^2)
人气:371 ℃ 时间:2020-05-08 00:58:36
解答
(a+2)(a-2)(a^4+4a^2+16)
=(a^2-4)(a^2+4)^2
=(a-2)(a+2)(a^2+4)^2
(x^2+2xy+y^2)(x^2-xy+y^2)
=[(x+y)^2](x+y)(x-y)
=(x-y)(x+y)^3
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