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计算:(x^2+2xy+y^2)/(x^2y+xy^2)-(x^2-2xy+y^2)/(x^2y-xy^2)
人气:171 ℃ 时间:2019-08-22 15:31:30
解答
:(x^2+2xy+y^2)/(x^2y+xy^2)-(x^2-2xy+y^2)/(x^2y-xy^2)
=(x+y)^2/[xy(x+y)]-(x-y)^2/[xy(x-y)]
=(x+y)/xy-(x-y)/xy
=(x+y-x+y)/xy
=2y/xy
=2/x
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