解下列方程:(1)4x²=1,(2)(x-1)²=9 (3)(x+3)²-4=0
(4)(x+1)²-3=0 (5)(3x+2)²-7=0(6)x²-6x=7
人气:123 ℃ 时间:2020-03-22 02:03:08
解答
(1)4x²=1
x²=1/4
x1=1/2 x2=-1/2
(2)(x-1)²=9
x-1=±3
x1=4 x2=-2
(3)(x+3)²-4=0
(x+3)²=4
x+3=±2
x1=-1 x2=-5
(4)(x+1)²-3=0
(x+1)²=3
x+1=±√3
x1=-1+√3 x2=-1-√3
(5)(3x+2)²-7=0
(3x+2)²=7
3x+2=±√7
3x=-2±√7
x1=(-2+√7)/3 x2=(-2-√7)/3
(6)
x²-6x=7
x²-6x-7=0
(x-7)(x+1)=0
x1=7 x2=-1
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