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1/3+1/15+1/35+1/63+……+1/9999=?
人气:327 ℃ 时间:2020-04-08 17:37:51
解答
原式=1/(1*3)+1/(3*5)+1/(5*7)+……+1/(99*101) =(3-1)/(3*1)+(5-3)/(5*3)+(7-5)/(7*5)……+(101-99)/(101*99) =1/2*[(1-1/3)+(1/3-1/5)+(1/5-1/7)……+(1/99-1/101)] =1/2*(1-1/101) =(1/...
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