若a+3b=0,则(1-b/a+2b)÷a^2+2ab+b^2/a^2-4b^2
人气：293 ℃ 时间：2020-04-13 21:40:20
解答
a+3b=0
a=-3b
原式=[(a+2b-b)/(a+2b)]÷(a+b)^2/(a+2b)(a-2b)
=(a+b)/(a+2b)×(a+2b)(a-2b)/(a+b)^2
=(a-2b)/(a+b)
=(-3b-2b)/(-3b+b)
=-5b/(-2b)
=5/2
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