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微分方程(x+1)dy/dx=y-y^2通解在线等,急
RT
人气:480 ℃ 时间:2019-12-20 07:29:53
解答
变量分离
dy/(y-y²)=dx/(x+1)
dy/y(1-y)=dx/(x+1)
[1/y+1/(1-y)]dy=dx/(x+1)
积分
ln/y/-ln/1-y/=ln/x+1/+c1
ln/y/(1-y)/-ln/x+1/=c1
ln/y/(1-y)(x+1)/=c1
C=±e^c1=y/(1-y)(x+1)
∴同解为:
y=c1(1-y)(x+1)
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