> 数学 >
【三角恒等变换】cos(33°-x)sin(63°-x)-cos(x+57°)sin(27°+x)
化简并求值
人气:496 ℃ 时间:2020-05-18 05:34:33
解答
cos(33°-x)sin(63°-x)-cos(x+57°)sin(27°+x)=cos[90°-(x+57°)]sin[90°-(x+27°]-cos(x+57°)sin(x+27°)=sin(x+57°)cos(x+27°)-cos(x+57°)sin(x+27°)=sin[(x+57°)-(x+27°)]=sin30°=1/2
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版