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sin(33°-x)cos(27°+x)+cos(33°-x)sin(27°+x)
人气:436 ℃ 时间:2020-05-28 13:15:51
解答
结构符合两角和正弦公式呀:sin(α+β)=sinαcosβ+cosαsinβsin(33°-x)cos(27°+x)+cos(33°-x)sin(27°+x)=sin[(33º-x)+(27º+x)]=sin(33º+27º)=sin60º=√3/2
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