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分式的相加1题
2/x-y + x/y - 1/x
人气:490 ℃ 时间:2020-06-13 18:17:05
解答
原式=2xy/[xy(x-y)]+x²(x-y)/[xy(x-y)]-y(x-y)/[xy(x-y)]=[2xy+x²(x-y)-y(x-y)]/[xy(x-y)]=(2xy+x³-x²y-xy+y²)/[xy(x-y)]=(x³-x²y+xy+y²)/[xy(x-y)]
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