已知方程yz+zx+xy=1确定了一个二元函数z=z(x,y),求dz
考试中,速度.
人气：428 ℃ 时间：2019-11-02 22:20:20
解答
先对x求导y*dz/dx + z + x * dz/dx + y = 0
所以dz/dx = -(z+y)/(x+y)
同理得dz/dy = -(z+x)/(x+y)
所以dz = -(z+y)/(x+y)dx -(z+x)/(x+y)dy
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