化简x^2-yz/[x^2-(y+z)x+yz]+y^2-zx/[y^2-(z+x)y+zx]+z^2-xy/[z^2-(x+y)_数学解答

化简x^2-yz/[x^2-(y+z)x+yz]+y^2-zx/[y^2-(z+x)y+zx]+z^2-xy/[z^2-(x+y)z+xy]

人气：322 ℃　时间：2020-01-28 00:42:57

解答

（x^2-yz）/[x^2-(y+z)x+yz]+（y^2-zx）/[y^2-(z+x)y+zx]+（z^2-xy）/[z^2-(x+y)z+xy]=（yz-x^2）/（x-y）(z-x)+（zx-y^2）/(y-z)(x-y)]+（xy-z^2）/(z-x)(y-z)=…………/（x-y）(y-z)(z-x)=0.