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求cosπ/9*cos2π/9*cos3π/9*cos4π/9
人气:382 ℃ 时间:2020-04-12 12:01:04
解答
cosπ/9*cos2π/9*cos3π/9*cos4π/9=(cosπ/9*cos2π/9*cos3π/9*cos4π/9)*8(sinπ/9)/8(sinπ/9)∵2cosπ/9*sinπ/9=sin2π/9∴原式=(4sin2π/9*cos2π/9*cos3π/9*cos4π/9)/8(sinπ/9)∵2sin2π/9*cos2π/9...
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