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因式分解法(2x-1)²=(3-x)²
人气:492 ℃ 时间:2020-03-26 16:21:45
解答
﹙2x-1﹚²-﹙x-3﹚²=0
﹙2x-1-x+3﹚﹙2x-1+x-3﹚=0
﹙x+2﹚﹙3x-4﹚=0
x1=﹣2
x2=3/4
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