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y=cos(xy)-x 求微分
人气:212 ℃ 时间:2020-06-11 06:55:29
解答
y'=-sin(xy)*(xy)'-1
y'=-sin(xy)(y+xy')-1
y'=-ysin(xy)-xy'sin(xy)-1
把y'弄到一边去
y'=(-ysin(xy)-1)/(1+xsin(xy))
dy=(-ysin(xy)-1)/(1+xsin(xy))dx
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