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数学
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已知tan(π+α)=3,求《2cos(π-α)-3(π+α)》÷《4cos(-α)+sin(2π-α)》的值
人气:320 ℃ 时间:2020-09-06 03:10:15
解答
tan(π+α)=3
tana=3
2cos(π-α)-3sin(π+α)/4cos(-α)+sin(2π-α)
=(-2cosa+3sinα)/(4cosα-sinα)
=(-2+3tanα)/(4-tanα)
=7
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